Title: Math 7 Review Geometry and Equations
Course: quiz duplicate error

Q: Use a protractor to measure the angle.

[Image]
- 20° (incorrect)
- 110° (This angle looks acute. Make sure you are looking at where the 0° is on your protractor.)
- 70° (correct)
- 40° (incorrect)
A: 70°

Q: Classify the angle as acute, right, obtuse, or straight.

[Image]
- Acute (Acute is less than 90°. This angle is more than 90°.)
- Obtuse (correct)
- Straight (A straight angle is 180°. This angle is less than that.)
- Right (A right angle is 90°. This angle is more than that.)
A: Obtuse

Q: What is the measure of an angle that is complementary to 65°?
- 15° (incorrect)
- 65° (incorrect)
- 25° (Correct. Two angles that are complementary have measured that add up to 90 degrees.)
- 115° (You want complementary angles, not supplementary angles.)
A: 25°

Q: Which pair of angles is supplementary?

[Image: Identify angles]
- ∠CUP and ∠PUT
- ∠PUT and ∠CUM
- ∠CUM and ∠MUC
- ∠CUP and ∠MUT
A: ∠CUP and ∠PUT

Q: Find the measure of  p

[Image: missing complementary angle; other angle 55 degrees]
- p = 55° (Those two angles are not congruent.)
- p = 35° (Correct.)
- p = 90° (p is only a part of the right angle)
- p = 125° (p is part of a right angle)
A: p = 35°

Q: Find the measure of  r

[Image: missing complementary angle; other angle 55 degrees]
- r = 55° (r is vertical angles with the angle that is 55 degrees.)
- r = 35° (Correct.)
- r = 90° (r is an acute angle)
- r = 125° (You need to subtract the 90 degree angle.)
A: r = 35°

Q: What equation will help you solve for x in the following figure?

[Image: angle equation line]
- 2x + 4x + 10 = 20 (I don't think the two bigger angles will equal 20°)
- 2x + 4x + 10 + 20 = 180
- 2x + 4x = 90 (There isn't a right angle in the figure.)
- 2x = 20 (Those two angles are not vertical angles. Look at the line instead.)
A: 2x + 4x + 10 + 20 = 180

Q: Solve for x:

[Image: angle equation line]
- x = 20
- x = 25
- x = 5 (Don't add x's to ones.)
- x = 50
A: x = 25

Q: What is the m∠DAB?

[Image: angle equation line]
- 20°
- 50°
- 110°
- 100°
A: 110°

Show the steps you use to solve the equation. Don't forget to simplify first!

-4(-6w – 3) = 12

Q: Mrs. Ling is putting a border around a chalkboard. The chalkboard is 48 inches long and 36 inches high.

[Image]

How many inches of border should she buy?
- 168 inches (To find the amount of border needed, add the length of each of the sides of the chalkboard. 36 + 48 + 36 + 48 = 168 The answer is 168 inches.)
- 84 inches (To find the amount of border needed, add the length of each of the sides of the chalkboard. 36 + 48 + 36 + 48 = 168 The answer is 168 inches.)
- 12 inches (To find the amount of border needed, add the length of each of the sides of the chalkboard. 36 + 48 + 36 + 48 = 168 The answer is 168 inches.)
- 120 inches (To find the amount of border needed, add the length of each of the sides of the chalkboard. 36 + 48 + 36 + 48 = 168 The answer is 168 inches.)
A: 168 inches

Q: What is the perimeter of this trapezoid?

[Image: Right Trapezoid; Bases 7 cm and 13 cm, height 8 cm, other side 10 cm]
- 25 cm (You need to add the lengths of all four sides together.)
- 38 cm
- 130 cm^2 (Perimeter is measured in centimeters, not in centimeters squared.)
- 40 cm^2 (The question asks for perimeter, not area.)
A: 38 cm

Q: What is the area of this trapezoid?

[Image: Right Trapezoid; Bases 7 cm and 13 cm, height 8 cm, other side 10 cm]
- 80 cm^2 (Well done.)
- 38 cm (The question asks for area, not perimeter.)
- 130 cm^2 (You only use the base lengths and the perpendicular height when calculating the area of a trapezoid. Don't use the 10 cm side.)
- 160 cm^2 (The area of a trapezoid is half of a parallelogram.)
A: 80 cm^2

Q: The figure is formed from rectangles. Find the total area. The diagram is not to scale.
[Image]
- 117 [Image]
- 44 [Image]
- 185 [Image]
- 97 [Image]
A: 97 [Image]

Q: Find the area.

[Image]
- 169 m^2 (correct)
- 84.5 m^2 (incorrect)
- 26 m^2 (incorrect)
- 52 m^2 (incorrect)
A: 169 m^2

The area of the following triangle is 64 ft^2.

[Image: missing height of triangle; 8 ft base]

a. Write an equation to find the height of the triangle

b. Find the height of the triangle

The length of a rectangle is 3 times the width of the rectangle. The perimeter of the rectangle is 88 inches. What is the width of the rectangle?

a. Write an equation to find the width of the rectangle

b. Find the width of the rectangle

Q: The area of this trapezoid is 112 cm^2. What is its height? Don't forget units!

[Image: Trapezoid Missing height; bases 13 cm, 15 cm]
A: 8

Q: When folded along the dotted lines, the net shown below will form a rectangular prism. What is the volume, in cubic units, of the prism?
[Image]
- 16 cubic units (After being folded, the dimensions of the prism will be 4 units by 2 units by 10 units. So the volume will be [Image])
- 136 cubic units (After being folded, the dimensions of the prism will be 4 units by 2 units by 10 units. So the volume will be [Image])
- 80 cubic units (After being folded, the dimensions of the prism will be 4 units by 2 units by 10 units. So the volume will be [Image])
- 1,000 cubic units (After being folded, the dimensions of the prism will be 4 units by 2 units by 10 units. So the volume will be [Image])
A: 80 cubic units

Q: When folded along the dotted lines, the net shown below will form a rectangular prism. What is the surface area, in cubic units, of the prism?
[Image]
- 68 square units (What about the other three sides?)
- 136 square units
- 120 square units (You left out two of the sides)
- 160 square units (Two of the sides are 2 units by 4 units)
A: 136 square units / 120 square units

Show the calculations you use to find the surface area of this triangular prism

[Image: Triangular prism]

Show the calculations you use to find the volume of this triangular prism

[Image: Triangular prism]

Q: Describe the cross section of this heptagonal prism and a plane parallel to its bases.

[Image: heptagonal prism]
- triangle
- rectangle
- heptagon
- trapezoid
A: heptagon

Q: Describe the cross section of this heptagonal prism and a plane perpendicular to its bases.

[Image: heptagonal prism]
- triangle
- rectangle
- heptagon
- trapezoid
A: rectangle

Q: The surface area of this box is 244 ft^2.  Which equation will help you find x?

[Image: Box Surface Area missing length]
- 7x + 2x + 14 = 244 (What about the other three sides?)
- 7x /2 + 2x / 2 + 14 / 2 = 244 (These are rectangles, not triangles.)
- 7(x)(2) = 244 (244 ft^2 is the surface area, not the volume.)
- 7x + 7x + 2x + 2x + 14 + 14 = 244
A: 7x + 7x + 2x + 2x + 14 + 14 = 244

Q: The surface area of this box is 244 ft^2.  What is the length of the missing side? Don't forget the units!

[Image: Box surface area missing length]
A: 12

Q: This A-frame cabin needs to have a volume of 270 ft^3. Which equation will help you find the height, h?

[Image: A frame cabin volume]
- 6(10)h = 270 (Remember that a triangle's area is half of a parallelogram.)
- 6(10)h / 2 = 270
- 6h + 10h + 10h = 270 (Volume is the area of the base of the prism times the height.)
- 6h + 10 = 270 (Volume is the area of the base of the prism times the height.)
A: 6(10)h / 2 = 270

Q: This A-frame cabin needs to have a volume of 270 ft^3. What should be the height of the cabin? Don't forget the units!

[Image: A frame cabin 270 cubic feet volume; missing height of triangle, base length 6 ft, depth 10 ft]
A: 9