Title: Math 7 Area Problems
Course: quiz duplicate error

Q: Carlton is assembling boxes and painting them so that they can be used as props in the school play. How many square inches of cardboard did he use to create the following box?

[Image]
- 160 square inches
- 80 square inches (Make sure you add up the area of all the sides.)
- 128 square inches (Make sure you add in the areas of the bases. [Image])
- 32 square inches (Make sure you add up the areas of all the sides. [Image])
A: 160 square inches

Q: Find the surface area of the given prism.

[Image]
- 500 square feet (Make sure you add the front and back as well.)
- 320 square feet (Make sure you add up the areas of all six sides.)
- 788 square feet
- 394 square feet (Make sure you add up the areas of all six sides.)
A: 788 square feet

Q: Find the surface area of the given prism.

[Image: triangular prism]
- 132 square meters
- 120 square meters (Make sure you add in the area of the bases.)
- 144 square meters (Remember that the area of a triangle is base * height / 2.)
- 200 square meters (Calculate the area of each of the five sides and add those areas together.)
A: 132 square meters

Q: What is the surface area of the rectangular prism?
[Image]
- 63 square centimeters (Use the formula for the surface area of a rectangular prism. [Image])
- 90 square centimeters (Use the formula for the surface area of a rectangular prism. [Image])
- 153 square centimeters (Use the formula for the surface area of a rectangular prism. [Image])
- 126 square centimeters (Use the formula for the surface area of a rectangular prism. [Image])
A: 126 square centimeters

The cereal bar box pictured below is a prism with parallelogram bases. Pretty cool packaging!

The base of each parallelogram has a length of about 6 inches and a height of 2 inches as marked. The box stands about 8 inches tall.

What is the surface area of the cereal bar box? Show your work.

[Image: prism packaging]
Feedback: Top and bottom parallelograms: 2*6 = 12 Front and back rectangles: 6*8 = 48 Side rectangles: 3*8 = 24 12 + 12 + 48 + 48 + 24 + 24 = 168 inches^2

Q: Miriam has 66 feet of fencing to make a rectangular vegetable garden. Which dimensions will give Miriam the garden with greatest area? The diagrams are not to scale.
- [Image]
- [Image]
- [Image]
- [Image]
A: [Image]

Q: You are planning parallelgram shaped parking spots as shown. You know the parking spots need to be 8 feet wide and each one should cover 160 ft^2 of area. What should be the height of the parallelogram?

[Image]
A: 20

Q: You are building a fence to hold pigs. You have 120 feet of fencing. You want the fence to be 3 times as long as it is wide. How wide should you make the fence to use all the fencing? Write an equation to help solve this problem.
- 3x + x = 120 (What about the other two sides of the fence?)
- 3x + x + 3x + x = 120 (That will work!)
- 3x(x) = 120 (Fencing is a perimeter problem, not an area problem.)
- 3 + x + 3 + x = 120 (The length is 3 times the width, not just 3.)
A: 3x + x + 3x + x = 120

Q: You are building a fence to hold pigs. You have 120 feet of fencing. You want the fence to be 3 times as long as it is wide. How wide should you make the fence to use all the fencing? Solve. Include the units in your answer. No spaces between the answer and the units.
A: 15

Q: The area of the trapezoid shown is 90 cm^2. The height of the trapezoid is 12 cm. The length of one of the bases is 7 cm. What is the length of the other base? Write an equation to help you solve this problem.

[Image]
- 7(12)b = 90 (Try again. You shouldn't multiply the bases together.)
- 12(7 + b) = 90 (Very close! That would be a parallelogram with a base that was both bases of the trapezoid added together.)
- 12(7 + b) / 2 = 90
- 7(12) / 2 = b (Try again. That looks more like triangle area.)
A: 12(7 + b) / 2 = 90

Q: The area of the trapezoid shown is 90 cm^2. The height of the trapezoid is 12 cm. The length of one of the bases is 7 cm. What is the length of the other base? Solve.

[Image]
A: 8

Q: You are making a large triangular flower garden. You have enough topsoil to cover 64 square yards of garden. The height of the triangle will be 8 yards. What will be the length of the base of the triangle? Write an equation to help you solve this problem.
- 8h = 64 (Remember that a triangle is half of a rectangle or parallelogram.)
- 8h / 2 = 64 (That will work!)
- (8 + h) / 2 = 64 (Think again about how to find the area of a triangle.)
- 8(64) / 2 = h (It might help to draw the triangle.)
A: 8h / 2 = 64

Q: You are making a large triangular flower garden. You have enough topsoil to cover 64 square yards of garden. The height of the triangle will be 8 yards. What will be the length of the base of the triangle? Solve. Include units in your answer. No spaces between your answer and the units.
A: 16

Q: This candy box is a triangular prism. It has the measurements shown. The surface area of the box is 231 cm^2. What is the height of the box? Write an equation that will help you solve this problem.

[Image]
- 2(3.5h / 2) + 3(21)(3.5) = 231
- 2(3.5h) + 3(21)(3.5) = 231 (Remember that triangle area is half the area of a parallelogram.)
- 3(21)(3.5)h = 231 (Remember that surface area is adding up the areas of all the sides.)
- 21(3.5h / 2) = 231 (Remember that surface area is adding up the areas of all the sides.)
A: 2(3.5h / 2) + 3(21)(3.5) = 231

Q: This candy box is a triangular prism. It has the measurements shown. The surface area of the box is 231 cm^2. What is the height of the box? Solve.

[Image]
A: 3

Q: Reynaldo needs to repaint the rectangular pool in his backyard. The pool measures 55 feet long, 28 feet wide, and 9 feet deep. How many square feet will he need to paint?

(Hint: he won't paint the top of the pool)
- 3034 ft^2 (Great job!)
- 4574 ft^2 (You counted the top of the pool. He isn't going to paint the top.)
- 2287 ft^2 (Did you count all the sides of the pool?)
- 1494 ft^2 (He will need to paint the bottom of the pool.)
A: 3034 ft^2

Q: The figure below shows the dimensions of Aman’s bedroom. Aman's walls are 9 units high. How can Aman find the surface area of just his walls? (Not the floor or ceiling)

[Image]
- 9(6 · 10 + 2 · 3) (That would be finding volume. You multiplied the area of the floor by the height.)
- 9(6 + 3 + 2 + 3 + 2 + 4 + 6 + 10) (That will do it. It is the perimeter of the room multiplied by the height.)
- 9(6 + 3 + 2 + 3 + 4) (What about the other walls? You only did the ones that had marked measures.)
A: 9(6 + 3 + 2 + 3 + 2 + 4 + 6 + 10)